A tin chloride ' $Q$ ' undergoes the following reactions (not balanced)\ $Q+\mathrm{Cl}^{-} ighta

Question

A tin chloride ' $Q$ ' undergoes the following reactions (not balanced)\ $Q+\mathrm{Cl}^{-} ightarrow X, Q+\mathrm{Me}_{3} \mathrm{~N} ightarrow Y, \mathrm{Q}+\mathrm{CuCl}_{2} ightarrow \mathrm{Z}+\mathrm{CuCl}$\ $X$ is monoanion having pyramidal geometry. Both $Y$ and $Z$ are neutral compounds. Choose the correct option(s).\

Professor PC Thomas Classes · Answer

(a,b)
$$
: \underset{(Q)}{\mathrm{SnCl}_2}+\mathrm{Cl}^{-} \rightarrow \underset{(X)}{\mathrm{SnCl}_3^{-}}
$$
$X$ is $s p^3$ hybridised with one lone pair of electrons.
$$\underset{(Q)}{\mathrm{SnCl}_2}+\mathrm{Me}_3 \mathrm{~N} \rightarrow \underset{(Y)}{\mathrm{SnCl}_2 \cdot\left[\mathrm{~N}\left(\mathrm{CH}_3\right)_3\right]}$$
$\mathrm{SnCl}_2$ is a Lewis acid while $\mathrm{Me}_3 \mathrm{~N}$ acts as Lewis base hence, there is a coordinate bond between them.
$$
\underset{(Q)}{\mathrm{SnCl}_2}+2 \mathrm{CuCl}_2 \rightarrow \underset{(Z)}{\mathrm{SnCl}_4}+2 \mathrm{CuCl}
$$

Sn in $\mathrm{SnCl}_4$ has +4 oxidation state and $\mathrm{SnCl}_4$ is tetrahedral with no lone pair.