The compound(s) which react(s) with $\mathrm{NH}_{3}$ to give boron nitride ( BN ) is(are)\

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Professor PC Thomas Classes · Answer

$(\mathrm{b}, \mathrm{c}): 2 \mathrm{~B}+2 \mathrm{NH}_{3} \xrightarrow{\Delta} 2 \mathrm{BN}+3 \mathrm{H}_{2}$ Here ' B ' is not a compound.\ $\mathrm{B}_{2} \mathrm{H}_{6}+\mathrm{NH}_{3} \xrightarrow{\Delta}(\mathrm{BN})_{x}$\ $\mathrm{B}_{2} \mathrm{O}_{3}+\mathrm{NH}_{3} \xrightarrow{\Delta} \mathrm{~B}_{2} \mathrm{O}_{3} \cdot \mathrm{NH}_{3} \xrightarrow{\Delta}$ $(\mathrm{BN})_{x}+\mathrm{H}_{2} \mathrm{O}$\ $\mathrm{HBF}_{4}+\mathrm{NH}_{3} \longrightarrow \mathrm{NH}_{4}^{+}\left[\mathrm{BF}_{4}ight]^{-}$