In the reaction : $2 X+\mathrm{B}_{2} \mathrm{H}_{6} \rightarrow\left[\mathrm{BH}_{2}(X)_{2}\right]+

Question

In the reaction : $2 X+\mathrm{B}_{2} \mathrm{H}_{6} ightarrow\left[\mathrm{BH}_{2}(X)_{2}ight]+\left[\mathrm{BH}_{4}ight]^{-}$, the amine(s) $X$ is(are)\

Professor PC Thomas Classes · Answer

( $a, b, c$ ) : The reaction of $\mathrm{B}_{2} \mathrm{H}_{6}$ with $\mathrm{NH}_{3}, 1^{\circ}$ and $2^{\circ}$ amines yield an ionic compound.\ \ However with $3^{\circ}$ amine, $\mathrm{B}_{2} \mathrm{H}_{6}$ forms an adduct.\ $\mathrm{BH}_{3}+\mathrm{N}\left(\mathrm{CH}_{3}ight)_{3} ightarrow\left(\mathrm{CH}_{3}ight)_{3} \mathrm{~N} ightarrow \mathrm{BH}_{3}$\