Assertion: During the boiling of water having temporary hardness, $Mg(HCO_{3})_{2}$ is converted to

Question

Assertion: During the boiling of water having temporary hardness, $Mg(HCO_{3})_{2}$ is converted to $MgCO_{3}$.\ Reason: The solubility product of $Mg(OH)_{2}$ is greater than that of $MgCO_{3}$.

Professor PC Thomas Classes · Answer

Both false. $Mg(OH)_{2}$ is formed (not $MgCO_{3}$) because $MgCO_{3}$ has a HIGHER Ksp than $Mg(OH)_{2}$.