For Freundlich adsorption isotherm, a plot of $log(x/m)$ (y-axis) and $log~p$ (x-axis) gives a strai

Question

For Freundlich adsorption isotherm, a plot of $log(x/m)$ (y-axis) and $log~p$ (x-axis) gives a straight line. The intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, absorbed per gram of adsorbent if the initial pressure is 0.04 atm, is $\_\_\_\_$ $	imes 10^{-4}$ g. $(log~3 = 0.4771)$

Professor PC Thomas Classes · Answer

Slope $1/n = 2$, Intercept $log~k = 0.4771 \implies k = 3$. $x/m = kP^{1/n} = 3 	imes (0.04)^2 = 0.0048 = 48 	imes 10^{-4}$ g.