20 mL of 0.5 M NaCl is required to coagulate 200 mL of $As_2S_3$ solution in 2 hours. The coagulatin

Question

20 mL of 0.5 M NaCl is required to coagulate 200 mL of $As_2S_3$ solution in 2 hours. The coagulating value of NaCl is

Professor PC Thomas Classes · Answer

Moles of NaCl = $20 	imes 0.5 = 10$ mmol. For 1000 mL solution, NaCl required = $(10/200) 	imes 1000 = 50$ mmol. Coagulating value is 50.