Assertion A: The reduction of a metal oxide is easier if the metal formed is in liquid state than so

Question

Assertion A: The reduction of a metal oxide is easier if the metal formed is in liquid state than solid state.\ Reason R: The value of $\Delta G^{\circ}$ becomes more on negative side as entropy is higher in liquid state than solid state.

Professor PC Thomas Classes · Answer

Liquids have higher entropy than solids. Forming a liquid metal provides a positive entropy change ($\Delta S$), making $\Delta G = \Delta H - T\Delta S$ more negative, thus facilitating reduction.