3.7 g of a gas at $25^{\circ}C$ occupied the same volume as 0.184 g of hydrogen at $17^{\circ}C$ and

Question

3.7 g of a gas at $25^{\circ}C$ occupied the same volume as 0.184 g of hydrogen at $17^{\circ}C$ and at the same pressure. What is the molecular weight of the gas?

Professor PC Thomas Classes · Answer

$V$ and $P$ are same, so $n_1T_1 = n_2T_2$. $(3.7/M) 	imes 298 = (0.184/2) 	imes 290$. Solving gives $M = 41.32$.