8 gram each of oxygen and hydrogen at $27^{\circ}C$ will have the total kinetic energy in the ratio

Question

8 gram each of oxygen and hydrogen at $27^{\circ}C$ will have the total kinetic energy in the ratio of:

Professor PC Thomas Classes · Answer

Total K.E. is proportional to the number of moles. $n(O_2) = 8/32 = 1/4$. $n(H_2) = 8/2 = 4$. Ratio = $(1/4) / 4 = 1:16$.