The value of PV for 5.6 litres of an ideal gas is $\_\_\_\_$ RT at N.T.P.

Question

Professor PC Thomas Classes · Answer

At NTP, 1 mole occupies 22.4 L. 5.6 L is $5.6/22.4 = 0.25$ moles. Since $PV = nRT$, $PV = 0.25 RT$.