The displacement-time graphs of two moving particles make angles of $60^{\circ}$ and $30^{\circ}$ wi

Question

The displacement-time graphs of two moving particles make angles of $60^{\circ}$ and $30^{\circ}$ with the $x$-axis respectively. The ratio of their respective velocities is

Professor PC Thomas Classes · Answer

(a) : The slope of a displacement-time graph gives velocity. \ $v_{1}=	an 60^{\circ} = \sqrt{3}$ \ $v_{2}=	an 30^{\circ} = \frac{1}{\sqrt{3}}$ \ So, $\frac{v_{1}}{v_{2}}=\frac{\sqrt{3}}{1/\sqrt{3}}= \sqrt{3} 	imes \sqrt{3} = 3: 1$