If a unit vector is represented by $0.6 \hat{i}+0.8 \hat{j}+c \hat{k}$ then the value of $c$ is

Question

Professor PC Thomas Classes · Answer

(a) : For a unit vector $\hat{n}$, its magnitude $|\hat{n}| = 1$. \ Therefore, $\sqrt{0.6^2 + 0.8^2 + c^2} = 1 \implies 0.36 + 0.64 + c^2 = 1 \implies 1.0 + c^2 = 1 \implies c^2 = 0 \implies c = 0$.