The horizontal range of a projectile is twice its maximum height. The angle of projection of the pro

Question

The horizontal range of a projectile is twice its maximum height. The angle of projection of the projectile is

Professor PC Thomas Classes · Answer

(a) : Horizontal range, $R=\frac{u^{2} \sin 2 	heta}{g}$. \ Maximum height, $H=\frac{u^{2} \sin ^{2} 	heta}{2 g}$. \ Given $R = 2H \Rightarrow \frac{u^{2} (2 \sin 	heta \cos 	heta)}{g} = 2 \frac{u^{2} \sin ^{2} 	heta}{2 g} \Rightarrow 2 \cos 	heta = \sin 	heta \Rightarrow 	an 	heta = 2$.