The radius of gyration of a rod of length $l$ about its equatorial axis

Question

Professor PC Thomas Classes · Answer

Moment of inertia of a rod about its equatorial axis is $I = \frac{Ml^2}{12}$. Radius of gyration $K = \sqrt{\frac{I}{M}} = \frac{l}{\sqrt{12}} = \frac{l}{2\sqrt{3}}$.