Area of the triangle with vertices $(6,3),(-3,5)$ and $(4,-2)$ is

Question

Professor PC Thomas Classes · Answer

Area $= \frac{1}{2} |x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)| = \frac{1}{2} |6(5 - (-2)) + (-3)(-2 - 3) + 4(3 - 5)| = \frac{1}{2} |42 + 15 - 8| = 24.5$ sq units.