Argument of $\frac{1+\mathrm{i} \sqrt{3}}{1+\mathrm{i}}$ is

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Professor PC Thomas Classes · Answer

$\arg\left(\frac{1+i\sqrt{3}}{1+i}ight) = \arg(1+i\sqrt{3}) - \arg(1+i) = 	an^{-1}(\sqrt{3}) - 	an^{-1}(1) = \frac{\pi}{3} - \frac{\pi}{4} = \frac{\pi}{12}$.