Two soap bubbles of unequal radii $R_1$ and $R_2$ ($R_1

Question

Two soap bubbles of unequal radii $R_1$ and $R_2$ ($R_1 < R_2$) are connected by a hollow capillary tube. Which of the following correctly describes the subsequent flow of air?

Professor PC Thomas Classes · Answer

(d) : The excess pressure inside a soap bubble is given by $\Delta P = \frac{4T}{R}$. Since $R_1 < R_2$, the pressure inside the smaller bubble is greater than the pressure inside the larger bubble. Fluids flow from a region of higher pressure to lower pressure. Thus, air will flow from the smaller bubble to the larger bubble, making the smaller bubble shrink and the larger one grow.