If the focal length of the eyepiece lens is decreased, then the magnifying power of

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Professor PC Thomas Classes · Answer

(c) : The magnifying power of a compound microscope is approximately $m = (L/f_o) 	imes (D/f_e)$. If the focal length of the eyepiece $f_e$ decreases, the magnification $m$ increases. The magnifying power of an astronomical telescope in normal adjustment is $M = f_o/f_e$. If $f_e$ decreases, the magnification $M$ also increases. Therefore, the magnifying power of both instruments will increase.