In the given circuit, what will be the steady state current?

Question

Professor PC Thomas Classes · Answer

(b) : In the steady state, the capacitor is fully charged and acts as an open circuit, meaning no current flows through its branch. The effective resistance of the circuit is $R_{eq} = 2 + 3 = 5 \Omega$. If the voltage $V$ is doubled to $20 \mathrm{~V}$, the new steady state current is $I = \frac{V}{R_{eq}} = \frac{20}{5} = 4.0 \mathrm{~A}$.