A uniform wire of resistance $200 \Omega$ is divided into 10 equal parts. The first 5 parts are conn

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A uniform wire of resistance $200 \Omega$ is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. These two separate combinations are then connected in series with each other. The resistance of this final combination is

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(c) : The resistance of the full wire is $200 \Omega$. When divided into 10 equal parts, each part has a resistance of $r = 200 / 10 = 20 \Omega$. The equivalent resistance of the first 5 parts in series is $R_s = 5 	imes 20 = 100 \Omega$. The equivalent resistance of the next 5 parts in parallel is $R_p = \frac{20}{5} = 4 \Omega$. When these two combinations are connected in series, the final equivalent resistance is $R_{eq} = R_s + R_p = 100 + 4 = 104 \Omega$.