In the given balanced Wheatstone bridge circuit, the net equivalent resistance between terminals $A$

Question

In the given balanced Wheatstone bridge circuit, the net equivalent resistance between terminals $A$ and $B$ will be

Professor PC Thomas Classes · Answer

(b) : In the original balanced Wheatstone bridge, the central resistor carries no current, and the equivalent resistance was $R_{eq} = \frac{14}{3} \Omega$. If every resistor in the network is scaled by a factor of 2, the bridge remains balanced. The equivalent resistance of any linear resistive network scales linearly with the individual resistances. Therefore, the new equivalent resistance is $R'_{eq} = 2 	imes R_{eq} = 2 	imes \frac{14}{3} = \frac{28}{3} \Omega$.