The equation of the circle with centre $(0,2)$ and radius 2 is

Question

Professor PC Thomas Classes · Answer

Equation: $(x-h)^2 + (y-k)^2 = r^2 \implies (x-0)^2 + (y-2)^2 = 2^2 \implies x^2 + y^2 - 4y + 4 = 4 \implies x^2 + y^2 - 4y = 0$.