The equation of the circle passing through $(0$, 0 ) and making intercepts $a$ and $b$ on the coordi

Question

The equation of the circle passing through $(0$, 0 ) and making intercepts $a$ and $b$ on the coordinate axes is

Professor PC Thomas Classes · Answer

If a circle passes through origin and has intercepts $a$ and $b$, its ends of diameter are $(a,0)$ and $(0,b)$. Equation is $(x-a)(x-0) + (y-0)(y-b) = 0 \implies x^2+y^2-ax-by=0$.