In an ideal transformer, the turns ratio is $N_s/N_p = 3/1$. The ratio of primary current to seconda

Question

In an ideal transformer, the turns ratio is $N_s/N_p = 3/1$. The ratio of primary current to secondary current ($I_p:I_s$) is equal to

Professor PC Thomas Classes · Answer

(b) : For an ideal transformer, the input power equals the output power, so $V_p I_p = V_s I_s$. This gives the relation $I_p/I_s = V_s/V_p$. We also know that voltage is directly proportional to the number of turns, meaning $V_s/V_p = N_s/N_p$. Therefore, $I_p/I_s = N_s/N_p = 3/1$. The ratio is 3:1.