In an AC circuit, a capacitor of capacitance $C$ is connected to an AC voltage source given by $V =

Question

In an AC circuit, a capacitor of capacitance $C$ is connected to an AC voltage source given by $V = V_0 \cos \omega t$. The displacement current $I$ flowing in the circuit is

Professor PC Thomas Classes · Answer

(b) : The charge on the capacitor at any instant is $q = CV = C V_0 \cos \omega t$. The displacement current $I$, which is equal to the conduction current in the connecting wires, is given by the rate of change of charge: $I = dq/dt = \frac{d}{dt}(C V_0 \cos \omega t) = -\omega C V_0 \sin \omega t$.