A compound $Y$ contains $32\%$ of $A$, $24\%$ of $B$ and the remaining percentage of $C$. Then, the

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A compound $Y$ contains $32\%$ of $A$, $24\%$ of $B$ and the remaining percentage of $C$. Then, the empirical formula of $Y$ is (Given atomic masses of $A = 32 \mathrm{~u}$; $B = 12 \mathrm{~u}$; $C = 11 \mathrm{~u}$)

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(d) : Percentage of $C = 100 - (32 + 24) = 44\%$. Number of moles of $A = \frac{32}{32} = 1$. Number of moles of $B = \frac{24}{12} = 2$. Number of moles of $C = \frac{44}{11} = 4$. The simplest whole number ratio of $A : B : C$ is $1 : 2 : 4$. Thus, the empirical formula of the compound is $A B_2 C_4$.