The absolute number of individual atoms present in $0.2 \mathrm{~mol}$ of a purely tetratomic gas is

Question

The absolute number of individual atoms present in $0.2 \mathrm{~mol}$ of a purely tetratomic gas is ($N_A = 6.02 	imes 10^{23} \mathrm{~mol}^{-1}$)

Professor PC Thomas Classes · Answer

(a) : A tetratomic gas implies that each individual molecule is composed of exactly 4 atoms. Therefore, the total number of atoms is calculated by multiplying the number of moles by the atomicity and Avogadro's number. Total atoms = $	ext{Moles} 	imes 	ext{Atomicity} 	imes N_A = 0.2 	imes 4 	imes 6.02 	imes 10^{23} = 0.8 	imes 6.02 	imes 10^{23} = 4.816 	imes 10^{23}$ atoms.