What is the exact weight of oxygen gas required for the complete combustion of 1.6 kg of methane ($\

Question

What is the exact weight of oxygen gas required for the complete combustion of 1.6 kg of methane ($\mathrm{CH}_4$)?

Professor PC Thomas Classes · Answer

(b) : The balanced equation for the combustion of methane is $\mathrm{CH}_4 + 2\mathrm{O}_2 ightarrow \mathrm{CO}_2 + 2\mathrm{H}_2\mathrm{O}$. Based on stoichiometry, $16 \mathrm{~g}$ of methane (1 mole) requires exactly $64 \mathrm{~g}$ of oxygen (2 moles) for complete combustion. Therefore, scaling up, $1.6 \mathrm{~kg}$ of methane will require $\frac{64}{16} 	imes 1.6 \mathrm{~kg} = 6.4 \mathrm{~kg}$ of oxygen.