The total number of nodal surfaces (combining both radial and angular nodes) present in a $5d$ atomi

Question

The total number of nodal surfaces (combining both radial and angular nodes) present in a $5d$ atomic orbital is exactly

Professor PC Thomas Classes · Answer

(a) : The total number of nodes (nodal surfaces) in any given atomic orbital is dictated entirely by its principal quantum number, given by the formula $(n - 1)$. This total is the sum of radial nodes $(n - l - 1)$ and angular nodes $(l)$. For a $5d$ orbital, $n = 5$. Therefore, the total number of nodes is $5 - 1 = 4$.