Match List I with List II and choose the correct answer. $\begin{aligned}
& extbf{List I} && extb

Question

Match List I with List II and choose the correct answer. $\begin{aligned}
&	extbf{List I} && 	extbf{List II} \
&	ext{A. Isothermal process} && 	ext{I. } q = 0 \
&	ext{B. Isochoric process} && 	ext{II. } \Delta U = 0 \
&	ext{C. Isobaric process} && 	ext{III. } W = 0 \
&	ext{D. Adiabatic process} && 	ext{IV. } q = \Delta H
\end{aligned}$

Professor PC Thomas Classes · Answer

(a) : For an isothermal process involving an ideal gas, the temperature remains constant, so the change in internal energy is zero ($\Delta U = 0$). In an isochoric process, volume is constant, so pressure-volume work is zero ($W = 0$). In an isobaric process, heat exchanged is equal to the change in enthalpy ($q = \Delta H$). In an adiabatic process, no heat is exchanged with the surroundings ($q = 0$).