Let $\mathrm{A}=\left\{(\mathrm{x}, \mathrm{y}): \mathrm{y}^2=4 \mathrm{x}\right\}$ and $\mathrm{B}=

Question

Let $\mathrm{A}=\left\{(\mathrm{x}, \mathrm{y}): \mathrm{y}^2=4 \mathrm{x}\right\}$ and $\mathrm{B}=\{(\mathrm{x}, \mathrm{y}):|\mathrm{x}-1|=\mathrm{y}\}$. Then $\mathrm{n}(\mathrm{A} \cap \mathrm{B})=$

Professor PC Thomas Classes · Answer

$|x-1|=y x-1= \pm y x+y=1$ and $x-y=1$ where $y \geq 0$ Draw the figures