A nuclide $A$ undergoes $\alpha$-decay and another nuclide $B$ undergoes $\beta$-decay

Question

Professor PC Thomas Classes · Answer

(a) : As already discussed in basic theory that in $\alpha$-emission the energy of all the emitted $\alpha$-particles are same so these will have almost the same speeds but in case of $\beta$-emission due to emission of neutrino the energy is distributed among beta particle and neutrino so emitted $\beta$-particles have different speeds.