A Zener diode is specified as having a breakdown voltage of 9.1 V , with a maximum power dissipation

Question

A Zener diode is specified as having a breakdown voltage of 9.1 V , with a maximum power dissipation of 364 mW . What is the maximum current the diode can handle?

Professor PC Thomas Classes · Answer

(a) : The maximum permissible current is \ $ I_{Z_{\max }}=\frac{P}{V_Z}=\frac{364 	imes 10^{-3}}{9.1}=40 \mathrm{~mA} . $