In Boolean algebra if $A=1$ and $B=0$, then the value of $A+\bar{B}$ is

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Professor PC Thomas Classes · Answer

(d) : Here, $A=1, B=0$, then $A+\bar{B}=1+\overline{0}=1+1=1$ $ 	herefore \quad A+B=1+0=1, $ \  But $B=0$ and $A \cdot B=1 \cdot 0=0$