To get output 1 at $R$, for the given logic gate circuit the input values must be

Question

Professor PC Thomas Classes · Answer

(a) : Output $R=\overline{(\bar{X}+Y)+\overline{(\bar{Y} \cdot X)}}$ $ =(\overline{\bar{X}+Y})(\bar{Y} \cdot X)=(X \bar{Y})(\bar{Y} \cdot X) $ \  So, for output $R=1, X=1, Y=0$