The number of divisors of the form $4 n+2(n \in N)$ of 240 is

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Professor PC Thomas Classes · Answer

$4 n+2=2 	imes(2 n+1)=2 	imes$ odd number $240=2^4 	imes 3 	imes 5$.Number of factors of the form $2 	imes$ odd number is $1 	imes 2 	imes 2=4$.