For a particle in uniform circular motion, the acceleration $\vec{a}$ at a point $P(R, heta)$ on t

Question

For a particle in uniform circular motion, the acceleration $\vec{a}$ at a point $P(R, 	heta)$ on the circle of radius $R$ is (Here $	heta$ is measured from the $x$-axis)

Professor PC Thomas Classes · Answer

(d) : For a particle in uniform circular motion, $a=\frac{v^2}{R}$ towards the centre of the circle $ \  	herefore \quad \vec{a}=\frac{v^2}{R}(-\cos 	heta \hat{i}-\sin 	heta \hat{j})=-\frac{v^2}{R} \cos 	heta \hat{i}-\frac{v^2}{R} \sin 	heta \hat{j} $