A swimmer wants to cross a river from point $A$ to point $B$. Line $A B$ makes an angle of $30^{\cir

Question

A swimmer wants to cross a river from point $A$ to point $B$. Line $A B$ makes an angle of $30^{\circ}$ with the flow of river. Magnitude of velocity of the swimmer is same as that of the river. The angle $	heta$ with the line $A B$ should be $\_\_\_\_$ ${ }^{\circ}$, so that the swimmer reaches point $B$.

Professor PC Thomas Classes · Answer

(b) : Let the velocity of swimmer which is equal to velocity of river be $v$. For both velocity vectors of same magnitude, the resultant would pass exactly midway. $V_M$ should be the bisector of $v_1$ and $v_2 . \quad 	herefore 	heta=30^{\circ}$