The pH of a buffer solution of $0.1 \mathrm{M} \mathrm{NH}_4 \mathrm{OH} \left[\mathrm{p} K_b=5.0\ri

Question

The pH of a buffer solution of $0.1 \mathrm{M} \mathrm{NH}_4 \mathrm{OH} \left[\mathrm{p} K_b=5.0\right]$ and $0.01 \mathrm{M} \mathrm{NH}_4 \mathrm{Cl}$ is

Professor PC Thomas Classes · Answer

$  (\mathrm{c}): \mathrm{pOH}  =\mathrm{p} K_b+\log \frac{[	ext { Salt }]}{[	ext { Base }]} \  =5+\log \frac{0.01}{0.1}=5+\log 10^{-1}\ =5-1=4  \  \mathrm{pH}=14-4=10  $