A student performs an experiment on photoelectric effect using two materials $A$ and $B$. A plot of

Question

A student performs an experiment on photoelectric effect using two materials $A$ and $B$. A plot of stopping potential $\left(V_0ight)$ versus frequency $(v)$ is as shown in the figure. The value of $h$ obtained from the experiment for both $A$ and $B$ respectively is (Given electric charge of an electron $=1.6 	imes 10^{-19} \mathrm{C}$ )

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(b): For metal $A$, Slope $=\frac{h}{e}=\frac{2-0}{(10-5) 	imes 10^{14}}$ \ $ 	ext { or } \quad h=\frac{2 	imes e}{5 	imes 10^{14}}=\frac{2 	imes 1.6 	imes 10^{-19}}{5 	imes 10^{14}}=6.4 	imes 10^{-34} \mathrm{~J} \mathrm{~s} $ \ For metal $B$, Slope $=\frac{h}{e}=\frac{2.5-0}{(15-10) 	imes 10^{14}}$ \ $ h=\frac{2.5 	imes e}{5 	imes 10^{14}}=\frac{2.5 	imes 1.6 	imes 10^{-19}}{5 	imes 10^{14}}=8 	imes 10^{-34} \mathrm{~J} \mathrm{~s} $