A satellite of mass $1000~kg$ revolves around the earth at a height of $2000~km$ from the surface. F

Question

A satellite of mass $1000~kg$ revolves around the earth at a height of $2000~km$ from the surface. Find its approximate time period of revolution. (Given: $M_e = 6 	imes 10^{24}~kg$, $R_e = 6400~km$)

Professor PC Thomas Classes · Answer

Time period $T = \frac{2\pi r}{v}$. We know $r = 8400~km = 8.4 	imes 10^6~m$ and $v = 6.9 	imes 10^3~m~s^{-1}$. $T = \frac{2\pi 	imes 8.4 	imes 10^6}{6.9 	imes 10^3} \approx 7646~s \approx 2.12~hours$.