In the redox reaction,\ $ \mathrm{Pb}_3 \mathrm{O}_4+8 \mathrm{HCl} \longrightarrow 3 \mathrm{PbCl}

Question

In the redox reaction,\ $ \mathrm{Pb}_3 \mathrm{O}_4+8 \mathrm{HCl} \longrightarrow 3 \mathrm{PbCl}_2+\mathrm{Cl}_2+4 \mathrm{H}_2 \mathrm{O} $

Professor PC Thomas Classes · Answer

(b) : $\mathrm{Pb}_3 \mathrm{O}_4$ is a mixture of PbO and \ $\mathrm{PbO}_2$. $ \mathrm{Pb}_3 \mathrm{O}_4 \equiv 2 \mathrm{PbO} \cdot \mathrm{PbO}_2 \ +8 \mathrm{HCl} \longrightarrow 3 \mathrm{PbCl}_2+\mathrm{Cl}_2+4 \mathrm{H}_2 \mathrm{O} $ \ In the reaction one $\mathrm{Pb}^{4+}$ ion is \ reduced to $\mathrm{Pb}^{2+}$ and two $\mathrm{Pb}^{2+}$ ions \ remain unchanged.