In a hydrogen atom, the radius of $n^{ ext {th }}$ Bohr orbit is $r_{n^{\cdot}}$ The graph between

Question

In a hydrogen atom, the radius of $n^{	ext {th }}$ Bohr orbit is $r_{n^{\cdot}}$ The graph between $\log \left(r_n / r_1ight)$ and $\log n$ will be

Professor PC Thomas Classes · Answer

(a): We know that $r_n \propto n^2$ or $\left(r_n / r_1ight)=n^2$ \ So, $\log \left(r_n / r_dight)=2 \log n$ \ Hence, the graph between $\log \left(r_n / r_1ight)$ and $\log n$ will be a straight line passing through origin. The positive slope is given by $	an 	heta=2$.